We have found possible mathematical expressions for the fields A and B and their difference as follows:

- Field A has given us the following equation / expression: 288 2^(2/3) E^(8/3) Power[log(8), (3)^-1]

- Field B has given us: (216 E log^5(3))/log^7(2)

- Unfortunately these two expressions are not quite similar albeit they both have 288 and 216 which are both 36*n. They also both include the E constant. And log()) functions.

- Equation / Expression for field-difference is in that regard not so different: 144*E^(5/2)*Sqrt[log(27)/log(2)] .

- The respective values of 36 are: 288=36*8, 216=36*6, 144=36*4.

Here Field A and B →:

Though "Integral Curves" for Field A plus "difference" looks different →:

This means that the equations or expressions may not be in tune quite yet, and that we had assumed initially but that is what we have for now.

From expressions suggested for Field A and maybe Field B.

- With the 2**(2/3)*e**(8/3)*pow(log(8),(3)^-1) we get close to 2*sqrt(72000/192000).

- Here we have 144000/2=72000 and also 32000*6=192000.

- 72/192 then is 0.75/2.

- So end product might be 36*x*(2*sqrt(72000/192000)) for Field A.

- This could be a hit or not.

- Interesting also is that this product can be expressed as either sqrt(2/3) or with the same output csc(θₜ/2), later being cosecant of tetrahedral angle.

- Investigating Field B in a similar manner has not yet proven ..anything..but we might just look at what we got from Field A possibly.

- We believe the system is might be pretty mathematical "tight" or systematic. So in a generalizations Filed A divided Field B might be just about 1.5.

- Otherwise the difference could of course be around 1.44 which is just as close to 1.455500168495149 as 1.5

- Many expressions surface looking at 1.455500168495149. sqrt(162000/72000) fits well for 1.5 though.

- 162000 being a "harmonic" of 162 which in 10f²+2 , f=4, the number of spheres in the 4th layer of closest packed spheres. (See Synergetics section 223 again.) etc.

- So Field B might be expressed as 36*x*(2*sqrt(72000/192000))*1.5 where derivative of x is 66.1362, close to 27*sqrt(6).

- Replacing 36*x with 6*x give the derivate 11.0227, giving close to 9*sqrt(3/2).

- However generalizing a bit (2*sqrt(72000/192000)) = log(x) we find..whatever..this is getting complicated.

- More to come, sooner or later.

- The two expressions seem to simplify to Field A=288*29 and Field B=432*29. We are going to to do various
calculations eventually to see if these fit.

- The original estimate 2**(2/3)*e**(8/3)*pow(log(8),(3)**-1) equals 29.160000075669835. Thus 29 maybe.

- Though e*log(3,5)/log(2,7); 5.209092016164562 which should be multiplied by 216 to give 1125.1638754915455,
though we double 216 to 432 and multiply by 29 here too...We trust the first expression we had to be the most correct.
They were all only based on guesses from software anyway. Thus we get 12528 instead, a higher exponent but..so
that it at least fit somewhat the original digit.

- So the original Field B is now larger than original field A, but otherwise it fits.

- So at least that leaves us with 8352+12528=20880; Looks like a "castling" of 28800..which might be alright.

- In 2nf²+2, 432 would be reduced to 216 by dividing by 2, which fit as 2*3**2+2=218. 218*2=436

- In 2nf²+2, 288 would fit as 1*12²+2=290.

- Total would then be 21054. Which unfortunately leaves us without 20880. We don't want that.

- Another possibly better , explanation is 288=2⁸*1.125 (s6), and 432 is 2⁸*1.6875. (1/(2**7)*216)

- Anyway we have sum(1-144)*2 = 20880 as total strength. 4176 as difference which → /2 is also 2088.

- The conceptual of it all may be difficult to explain, with as few details as here.

- 12528 seems like a Harmonic of Schuman Resonance → 783*2*2*2*2=12528.

- Also 12528/6 is 2088 again. But 12528 → /2/2 we have 3132 to subtract 2**11..which leaves 1048 which is 24 away from 1024, for
better or worse.

- Both field values squared and divided on each other, give multiplied with 36 exactly 16.

- 69755904/156950784*36=16. The reverse give 2.25 divided.

- Curiously total field strength 20880*6 is 125280 a harmonic of Field B..

- Next subtract Field A: 125280-8352=116928 → /216 = 541.3333333333334

- 541.3333333333334 → 1/x → *6*6*6*6*6 = 14.364532019704434 → 1.44-x → 1/x = 28.194444444444.

- 28.194444444444*6 == 169.16666666666 → **2 = 28617.361110885555 Matter-Antimatter.

- → /2 = 14308.680555442777 speed of light → 1/x = 6.988764590314494e-05 gravity factor...

- The problem with the above calculation is as usual to create a "concept" out of it...

- ..we have here Field B inside both fields..which subtracted Field A and manipulated..etc..

- Though 169.16666666666 which let the Wadsworth constant turn up again in it's equation:

- 169.16666666666 = (5075*Wwad)/9 from which we get 5075.

- So → 1/(12528/5075)*216 == 87.5 → *2*2*2 = 700 Harmonic. Little logic.

- 700*2**11=1433600 → 1440000-x = 6400..

- So → 1/(12528/5075)*216*2048 = harmonic 1433600. Which in harmonic equation 3 give: 69698.22108069912 as a result.

- Curiously 20880/16 is composed of 783+522, but in hertz 1305 is equal to about 78300 RPM.

- 1305/522 is exactly 2.5.

- 20880 RPM is about 348 hertz which is 2*6*29.

- 522 hz is equal to 31320 RPM which divided by 4 is 7830...

- 522 *2 *2 → 2088.

- Ayers Rock, or "Uluru" is standing 348 meters into the air.

- 29*1.125*16 = 522.0 ,

- 3393 (Pulse of the universe p. 43) → /8352 * 32 = 13.

- 3392 / 12528 = 0.2708333333333333. → *6 = 1.625 → *8 = 13.

- 13*216=2808

- Some height or base, or both, of the Great Pyramid is 5832 a "castling" of 8352.

- 1/(8352/5832)=1.4320987654320987 → 1.44-x → 1/x = 126.562499999999 or 126.5625.→

- → x/2/2 → x*8*8/(9*9) == 25.→ /6000 → /60 == 6.944444444444444e-05.

- → 1/x == 14400.0 so the Great Pyramid and Field A share harmonic 14400.

- 12528/5832*216=464. 464=29*2*2*2*2. → 2880-(464*6)=96. → 96/2 → 144/48=3. → 12528/3 → 5832/4176 = → 1/1.396551724137931

- → *2 → 1.44-1.4320987654320987 = → → 0.7901234567901234*1296 = 1024 == 2*2*2*2*2*2*2*2*2*2...

- We get 4176 from Field B and combine with pyramid digit to get a light-speed eventually. Light speed is then subtracted
from max speed and ..., and multiplied by 6⁴ to get difference as harmonic 1024 or 2**n. Roughly. The whole operation is rather
complicated....but shows that also Field B can be associated with The Great Pyramid.

- 12528/1024 → 12.234375*64 = 783. Of course → *16 = 12528..

- This leaves out that we usually think of Schuman Resonance as 1/128=0.0078125. Harmonic different with 7.83 hz
would be harmonic 175.

- 175*2*2*2*2*2*2*2*2*2*2*2*2*2=143360 as stated earlier. Difference from max light speed harmonic, is 6400.

- Working backwards from 781.25 → *16 we get 12500, 28 less than Field B. → 12500/432 → 29-x → x*216 = 14?

- Boolean: 12528 and 8352 is 8352. 12528 or 8352 is 12528. 12528 xor 8352 is 4176 (field difference). Thus the values,
if it's important, seems compatible in boolean algebra..

- Maybe some of these things above show that the values 8523 and 12528 might work. We suppose much more is needed
to prove anything.

12528 has the following factorials: 1,2,3,4,6,8,9,12,16,18,24,27,29,36,48,54,58,72,87,108,116,144,174,216,232,261, 232,261,348,432,464,522,696,783,1044,1392,1566,2088,3132,4176,6264 and 12528. Many interesting factorials and some that we have not noticed before..? Total of factorials is 37200.

8352 has more or less the same factorials except 27,54,108,216,2784. But 96, 288, 928, and 2784..possibly..

Total is here 24570..

INDEX. (C) Krister Lilleland 2008-2017.