Some kind of series from the Centered Hexagonal Numbers, divided by six each.

#.....Number Divided by 36 HarmonicN*Wad/54Sub-harmonic /36/2**2
110.02777777777777777650.006944444444444444"Harmonic for each electron"- Cathie.
270.1944444444444444535
3190.527777777777777895
4371.02777777777777771850.2569444444444444
5611.6944444444444444305 Cathie harmonic of proton or electron.
Or something about "Wavelength and Kinetic Energy"
described below. Light wavelength 238 nm*
6912.5277777777777777455
7127 3.5277777777777777635
8 169 4.694444444444445845
9 217 6.02777777777777810851.5069444444444444
10 271 7.5277777777777781355
11 331 9.1944444444444451655
12 397 11.02777777777777919852.756944444444444
13 469 13.02777777777777923453.256944444444444
14 547 15.1944444444444452735
15 631 17.527777777777783155
16 721 20.0277777777777836055.00694444444444
17 817 22.6944444444444434085
18 919 25.527777777777784595
19 1027 28.527777777777785135
20 1141 31.6944444444444435705


A long-shot.

We find on google: "When light with a wavelength of 238 nm is incident on a certain metal surface, electrons are ejected with a maximum kinetic energy of 3.37 10-19 J. Determine the wavelength of light that should be used to double the maximum kinetic energy of the electrons ejected from this surface."

Answer:"ke = E - we = hc/L - we = 3.37E-19 J; where L = 238E-9 m. Find the work function we = hc/L - ke = 6.63E-34*299E6/238E-9 - 3.37E-19 = 4.95929E-19 J.

Then E = we + 2*ke = hc/L; so that L = hc/(we + 2ke) = 6.63E-34 * 299E6/(4.95929E-19 + 2*3.37E-19) = 1.69444E-07 m (169 nm) ANS.

238 nm is an invisible wavelength of light. We did some math-trick on this 238/61 → 3.901639344262295 * 305 → 1190 / 328 = 5. Does this indicate that this wavelength of light has some affinity with this table? Trick unfortunately. But we do have trapped a 39...value here, also 1190 whatever that is.

If we try to find wavelength 438 in relation to 1190 we get 238/96≃2.5053 as x for 438*x=1190. 238 again.... could be something or co-incidence.

Percolation Threshold and previous integrals from (sqrt(((n/3)*(n*5)/2)*2.9))/n.

We computed all of the integers from integration of the above formula and most matched something like in the title in the wolfram mathematica notebook here.

There are some stuff not included here.

1.55456 Pc (diamond bond) + 7/6 Exact value
3.10913 2pc (diamond bond) + 7/3 Exact Value
4.66369 (8Pc(simple cubic bond)/3)+4 4.66346666
6.21825 (7pc(Honeycomb site)/4)+5 Exact value
7.77282 (30Pc(BCC Bond)/7)+7 7.77271428
9.32738 24Pc(BCC BOND)+5 Exact Value
10.8819 10Pc(Diamond Bond)+7, 20Pc(6D Bond)+9 Exact and 10.8840000
12.4365 Pc(diamond site)+12 12.4300000
13.9911 nothing
15.5456 nothing


Index.